1. Diketahui : f = 8 cm
s = 4 cm
Ditanaykan : Jarak bayangan (s’ ), sifat bayangan
Jawab :
Hubungan antara jarak focus (f), jarak benda (s) dan jarak bayangan (s’) di rumuskan:
1/ f = 1/s + 1/s’
1/8 = 1/4 + 1/s’
1/s’ = 1/8 – ¼
= 1/8 – 2/8
= - 1/8
s’ = - 8/1 = - 8 cm